Biology for a-level students home work

segwanga

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BIOLOGY HOME WORKS SERIES
For advanced level students, observe the date and day please

MONDAY 21/03/2011

1. A biologist isolated a sample of an enzyme called lactase from the intestinal lining of of a calf. The substrate of lactase is lactose which is broken into galactose and glucose. She prepared 2% enzyme solution with different concentrations of lactose and measured the rate of galactose production. She recorded the results as shown below.
Lactose concentration
0
5%
10%
20%
30%
Enzyme concentration
2%
2%
2%
2%
2%
Reaction rate
0
25
50
65
65

(i)Sketch a graph of rate versus lactose concentration
(ii)Explain the relationship between the rate of reaction and the substrate
concentration.

TUESDAY 22/03/2011
2. (a)Define each of the following
(i)Lipid
(ii)Carbohydrate
(b)Why do many organisms store lipids rather than carbohydrates?
WEDNESDAY 23/03/2011
3.State the role of each of the following
(i)Enterokinase
(ii)Columnar epithelium
(iii)Goblet cells
THURSDAY 24/03/2011
4.(i)Why is photorespiration more common in C3 plants than C4 plants?
(ii)Why are C4 plants more efficient in photosynthezing than C3

FRIDAY 25/03/2011

5. (a)Define each of the following
(i)ATP
(ii)Activator
(iii)Coenzyme
(b)Briefly explain the induced fit and Lock and Key model of enzyme action

SATURDAY 26/03/2011
6. (a)Define each of the following
(i) Autolysis
(ii) Outophagy
(iii) Pinocytosis
(b)Discuss four factors which affect the rate of enzyme catalyzed reactions.

SUNDAY 27/03/2011
7.(a) Describe the structure and functions of ATP
(b)Why is ATP known as the “the common energy currency” of the cell?


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i remember only one thing C6H12O6 is type of food...
 
Hapa naona mwalimu nitapata refresher ya biology!! muda mrefu sana sijafanya hiii...ni na digrii ya chemistry!
 
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