Find the value of x

2^x = 4x( 2 power x is equal to 4x).Show your working clearly.Any one who can solve it help me.

Mutta said:

2^x = 4x( 2 power x is equal to 4x).Show your working clearly.Any one who can solve it help me.

Click to expand...

1) Apply log ya base 10:
log2^x=log4x
xlog2=log4+logX
xlog2=log(4+x)
x=log(4+x)/log2
x=(4+x)/2
2x=4+x
x=4

Kituko said:

1) Apply log ya base 10:
log2^x=log4x
xlog2=log4+logX
xlog2=log(4+x)
x=log(4+x)/log2
x=(4+x)/2
2x=4+x
x=4

Click to expand...

big up mkuu

Kituko said:

1) Apply log ya base 10:
log2^x=log4x
xlog2=log4+logX
xlog2=log(4+x)
x=log(4+x)/log2
x=(4+x)/2
2x=4+x
x=4

Click to expand...

Hapana mkuu cheki vizuri kwenye blue!Ipo hivi
2[SUP]x[/SUP]=4x
Apply log base ten
log(2[SUP]x[/SUP])=log(4x)
xlog2=log4 +logx
xlog2=log(2[SUP]2[/SUP]) +logx
xlog2=2log2 +logx
xlog2-2log2 =logx
(x-2)log2 =logx
x-2=logx/log2
x-2= x/2
2x-4 =x
2x-x =4
x=4
Umegundua kosa la kikanuni hapo?

Chakunyuma said:

Hapana mkuu cheki vizuri kwenye blue!Ipo hivi
2[SUP]x[/SUP]=4x
Apply log base ten
log(2[SUP]x[/SUP])=log(4x)
xlog2=log4 +logx
xlog2=log(2[SUP]2[/SUP]) +logx
xlog2=2log2 +logx
xlog2-2log2 =logx
(x-2)log2 =logx
x-2=logx/log2
x-2= x/2
2x-4 =x
2x-x =4
x=4
Umegundua kosa la kikanuni hapo?

Click to expand...

OYA logx/log2 ni logx base2 sio logx/2

Gonga hapa: https://www.jamiiforums.com/jukwaa-la-elimu-education-forum/178996-msaada-wa-haraka-hii-hesabu.html

Problem has no exact solution. Can be solved graphically or by numerical methods.


Graphic solution:

Draw curve y=2^x and the line y= -4x . Point of intersection of curve and line is the required solution. (lies between x=-1 and x=0)

Kituko said:

1) Apply log ya base 10:
log2^x=log4x
xlog2=log4+logX
xlog2=log(4+x)
x=log(4+x)/log2
x=(4+x)/2
2x=4+x
x=4

Click to expand...

Chakunyuma said:

Hapana mkuu cheki vizuri kwenye blue!Ipo hivi
2[SUP]x[/SUP]=4x
Apply log base ten
log(2[SUP]x[/SUP])=log(4x)
xlog2=log4 +logx
xlog2=log(2[SUP]2[/SUP]) +logx
xlog2=2log2 +logx
xlog2-2log2 =logx
(x-2)log2 =logx
x-2=logx/log2
x-2= x/2
2x-4 =x
2x-x =4
x=4
Umegundua kosa la kikanuni hapo?

Click to expand...

Hauwezi ku cancel logarithms kihivyo.

Ongezea na hii 3[SUP]X[/SUP]=9X

Haa mnanikumbusha mabanda yangu ya number.

DASA said:

Gonga hapa: https://www.jamiiforums.com/jukwaa-la-elimu-education-forum/178996-msaada-wa-haraka-hii-hesabu.html

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DASA naona hesabu yako imejirudia.

DASA said:

Gonga hapa: https://www.jamiiforums.com/jukwaa-la-elimu-education-forum/178996-msaada-wa-haraka-hii-hesabu.html

Click to expand...

DASA kutumia desa haimo mkuu..:nono:

Hapa naona tu kanuni mpya za log!

Dah! Jamani eeh! Mbona Kang ameshaelezea namna ya kutumia graph kusolve hyo hesabu? Log concept haipandi hapo jamani,mnaotumia log hapo ni Uongo unaofanana na Ukweli. Tumieni graph acheni uvivu watanzania,haya mabishano tunayoyaendeleza hapa,tulishabishana sana tukiwa shule,sasa tuuelewe ukweli tufanye kazi ya kuboresha maisha yetu.

Kang said:

Hauwezi ku cancel logarithms kihivyo.

Click to expand...

Bg up kaka! Waambie hao,mi nilishaelewa tangu zamani,lakini humu watu hawataki kubadilika.

Kang said:

Hauwezi ku cancel logarithms kihivyo.

Click to expand...

Bg up kaka Kang! Waambie hao,mi nilishaelewa tangu zamani,lakini humu watu hawataki kubadilika.

Husninyo said:

DASA naona hesabu yako imejirudia.

Click to expand...

Niambie mtaalam, Ndio mana ikabidi niwape ule mtiririko ili wadadavue na kudadavulika wenyewe.

Kituko said:

1) Apply log ya base 10:
log2^x=log4x
xlog2=log4+logX
xlog2=log(4+x)
x=log(4+x)/log2
x=(4+x)/2
2x=4+x
x=4

Click to expand...

hapo kwenye
x = l(4+x)/log2
x=4+x/2 sio kweli.there no such a law in logarithms