mboni inaonekana kama copy and paste hiyo mzee hasa kuanzia hapo kwenye bluu
I am back now!!
2Logx = x/25
Divide by x both sides
(2/X)logx = 1/25
logx [SUP](2/x)[/SUP] = 1/25
Remove log sign
10[SUP](1/25) [/SUP]= x[SUP](2/x)
[/SUP]Take √ both sides(but √ means power 1/2)
so, from √10[SUP](1/25) [/SUP]=√x [SUP](2/x)[/SUP]
we will get
10[SUP]1/25(1/2)[/SUP] = x[SUP]2/x(1/2)
[/SUP]simplify on exponents
10[SUP]1/50[/SUP] =x[SUP]1/x
[/SUP]10[SUP]2/2*1/50[/SUP] =x[SUP]1/x[/SUP] note 2/2=1, so will not change the value of exponent
10[SUP]2(1/100)[/SUP] =x[SUP]1/x
[/SUP]100[SUP]1/100[/SUP] = x [SUP]1/x[/SUP]
x = 100
O-Level, Azania '96 - '99
I am back now!!
2Logx = x/25
Divide by x both sides
(2/X)logx = 1/25
logx [SUP](2/x)[/SUP] = 1/25
Remove log sign
10[SUP](1/25) [/SUP]= x[SUP](2/x)
[/SUP]Take √ both sides(but √ means power 1/2)
so, from √10[SUP](1/25) [/SUP]=√x [SUP](2/x)[/SUP]
we will get
10[SUP]1/25(1/2)[/SUP] = x[SUP]2/x(1/2)
[/SUP]simplify on exponents
10[SUP]1/50[/SUP] =x[SUP]1/x
[/SUP]10[SUP]2/2*1/50[/SUP] =x[SUP]1/x[/SUP] note 2/2=1, so will not change the value of exponent
10[SUP]2(1/100)[/SUP] =x[SUP]1/x
[/SUP]100[SUP]1/100[/SUP] = x [SUP]1/x[/SUP]
x = 100
O-Level, Azania '96 - '99
I am back now!!
2Logx = x/25
Divide by x both sides
(2/X)logx = 1/25
logx [SUP](2/x)[/SUP] = 1/25
Remove log sign
10[SUP](1/25) [/SUP]= x[SUP](2/x)
[/SUP]Take √ both sides(but √ means power 1/2)
so, from √10[SUP](1/25) [/SUP]=√x [SUP](2/x)[/SUP]
we will get
10[SUP]1/25(1/2)[/SUP] = x[SUP]2/x(1/2)
[/SUP]simplify on exponents
10[SUP]1/50[/SUP] =x[SUP]1/x
[/SUP]10[SUP]2/2*1/50[/SUP] =x[SUP]1/x[/SUP] note 2/2=1, so will not change the value of exponent
10[SUP]2(1/100)[/SUP] =x[SUP]1/x
[/SUP]100[SUP]1/100[/SUP] = x [SUP]1/x[/SUP]
x = 100
O-Level, Azania '96 - '99
mboni inaonekana kama copy and paste hiyo mzee hasa kuanzia hapo kwenye bluu
2 log x= x/25
50 log x = x
baada ya hapo ni kupachika namba kulia kushoto na balance inapatikana @ x= 100
50 log 100 = 100
50*2 = 100
100 = 100
since i know X = 100 then solution to suit my answer will be forged as well