Math challenge

Sawa
Kama vipi shusha nondo hapa tupate jibu.
(sin(78Β°)/sin(18Β°)) x (sin(24Β°)/sin(18Β°)) x (sin(DBA)/sin(DBC)) = 1

sin(78Β°) approx 0.9781,
sin(18Β°) approx 0.3090
sin(24Β°) approx 0.4067

0.9781/0.3090 approx 3.165
0.4067/0.3090 approx 1.316

3.165 Γ— 1.316 approx 4.166

4.166 Γ— sin(DBA)/sin(DBC) = 1

sin(DBA)/sin(DBC) approx 0.24

Let angle DBA = y, then angle DBC = 42Β° - y

sin(y)/sin(42Β°- y) approx 0.24

Solving numerically, let's try y = 8Β°
sin( 8Β°) approx 0.1392, sin(34Β°) approx 0.5582

0.1392/0.5582 approx 0.249 (close to 0.24)

So, angle DBA approx 8 and angle DBC approx 34

Angle ADB = 180Β° - 78Β° - 8Β° = 94Β°

Angle ADC + angle ADB + angle BDC = 360Β°
Angle BDC = 360Β° - 144Β° - 94Β° = 122Β°
x = 122Β°
 
Ebwana eeh! 🫑
 
Challenge ya kufunga siku.. Wakali wa vibox uwanja wenu huu.
 
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