p { margin-bottom: 0.08in; }
1+1=1
Proof
Let a= 1 .(i)
Multiply by a in both sides
a×a = 1×a ..(ii)
From eqn (ii) reduce 1 in both sides
a²-1 = a-1 (iii)
But a²-1 = (a+1)(a-1) -This is factorization of quadratic equation
There fore
(a +1)(a-1) = (a-1) .(iv)
Divide by (a-1) both sides
(a+1)(a-1) = (a-1)
(a-1) (a-1)
(a+1) = 1 ..(v)
But from equation number (i) we let a=1.Take it and substitute into equation number (v)
Hence
1 +1 = 1
p { margin-bottom: 0.08in; }
1+1=1
Proof
Let a= 1…………….(i)
p { margin-bottom: 0.08in; }
1+1=1
Proof
Let a= 1…………….(i)
Multiply by a in both sides
a×a = 1×a…………..(ii)
From eqn (ii) reduce 1 in both sides
a²-1 = a-1………………(iii)
But a²-1 = (a+1)(a-1) -This is factorization of quadratic equation
There fore
(a +1)(a-1) = (a-1)…….(iv)
Divide by (a-1) both sides
(a+1)(a-1) = (a-1)
(a-1) (a-1)
(a+1) = 1…………………..(v)
But from equation number (i) we let a=1.Take it and substitute into equation number (v)
Hence
1 +1 = 1
mzee wa kutegua mabomu umestukia tunapelekwa chaka eeehI dont see an 'a' in the formula you are trying to prove. Labda ungesema, let 1= a (In which case you would be asuming that we dont know what '1' is but we know what an 'a' is!).
p { margin-bottom: 0.08in; }
1+1=1
Proof
Let a= 1…………….(i)
Multiply by a in both sides
a×a = 1×a…………..(ii)
From eqn (ii) reduce 1 in both sides
a²-1 = a-1………………(iii)
But a²-1 = (a+1)(a-1) -This is factorization of quadratic equation
There fore
(a +1)(a-1) = (a-1)…….(iv)
Divide by (a-1) both sides
(a+1)(a-1) = (a-1)
(a-1) (a-1)
(a+1) = 1…………………..(v)
But from equation number (i) we let a=1.Take it and substitute into equation number (v)
Hence
1 +1 = 1
p { margin-bottom: 0.08in; }
1+1=1
Proof
Let a= 1…………….(i)
Multiply by a in both sides
a×a = 1×a…………..(ii)
From eqn (ii) reduce 1 in both sides
a²-1 = a-1………………(iii)
But a²-1 = (a+1)(a-1) -This is factorization of quadratic equation
There fore
(a +1)(a-1) = (a-1)…….(iv)
Divide by (a-1) both sides
(a+1)(a-1) = (a-1)
(a-1) (a-1)
(a+1) = 1…………………..(v)
But from equation number (i) we let a=1.Take it and substitute into equation number (v)
Hence
1 +1 = 1
You let a=1,so wen u divide by (a-1),means dat you divide by zero both sides,mathematicaly dis is incorrect and the answer is undefined and not 1 as u show us!
p { margin-bottom: 0.08in; }
1+1=1
Proof
Let a= 1…………….(i)
Multiply by a in both sides
a×a = 1×a…………..(ii)
From eqn (ii) reduce 1 in both sides
a²-1 = a-1………………(iii)
But a²-1 = (a+1)(a-1) -This is factorization of quadratic equation
There fore
(a +1)(a-1) = (a-1)…….(iv)
Divide by (a-1) both sides
(a+1)(a-1) = (a-1)
(a-1) (a-1)
(a+1) = 1…………………..(v)
But from equation number (i) we let a=1.Take it and substitute into equation number (v)
Hence
1 +1 = 1
p { margin-bottom: 0.08in; }
1+1=1
Proof
Let a= 1…………….(i)
Multiply by a in both sides
a×a = 1×a…………..(ii)
From eqn (ii) reduce 1 in both sides
a²-1 = a-1………………(iii)
But a²-1 = (a+1)(a-1) -This is factorization of quadratic equation
There fore
(a +1)(a-1) = (a-1)…….(iv)
Divide by (a-1) both sides
(a+1)(a-1) = (a-1)
(a-1) (a-1)
(a+1) = 1…………………..(v)
But from equation number (i) we let a=1.Take it and substitute into equation number (v)
Hence
1 +1 = 1
Mtihani mwema kaka, Kwa mfumo huu huwezi kwepa F ya Hisabati. Tutaonana Kantalamba HKLp { margin-bottom: 0.08in; }
1+1=1
Proof
Let a= 1…………….(i)
Multiply by a in both sides
a×a = 1×a…………..(ii)
From eqn (ii) reduce 1 in both sides
a²-1 = a-1………………(iii)
But a²-1 = (a+1)(a-1) -This is factorization of quadratic equation
There fore
(a +1)(a-1) = (a-1)…….(iv)
Divide by (a-1) both sides
(a+1)(a-1) = (a-1)
(a-1) (a-1)
(a+1) = 1…………………..(v)
But from equation number (i) we let a=1.Take it and substitute into equation number (v)
Hence
1 +1 = 1