Simple mathematics question

Kibishi · May 2, 2015

Given CLASS MARK and SIZE OF CLASS INTERVALS are 5 and 9 respectively.Find
(i)UPPER LIMIT
(ii)LOWER LIMIT
N.B:Upper boundary=upper limit+0.5
and,
Lower boundary=lower limit-0.5

itakiamo · May 2, 2015

let x=upper limit and y=lower limit
classmark=(x+y)/2=5 then x+y=10(first equation)
Size of class interval=(x+0.5)-(y-0.5)=9 then x-y+1=9
x-y=8(second equation) by using simultenous equation
x=9 and y=8, therefore upper limit is 9 and lower limit is 8

Kibishi · Jun 20, 2015

itakatikiamo said:
let x=upper limit and y=lower limit
classmark=(x+y)/2=5 then x+y=10(first equation)
Size of class interval=(x+0.5)-(y-0.5)=9 then x-y+1=9
x-y=8(second equation) by using simultenous equation
x=9 and y=8, therefore upper limit is 9 and lower limit is 8

Hatua zote upo sahihi mkuu itakatikiamo.
Hebu solve vizuri hiyo simultaneous equation.

Cndoh Jr · Jun 21, 2015

Upo vzur mkuu ila umejsahau kdogo kwny kusolv simultaneous eqn... ..upper ni 9 na lower ni 1

Simple mathematics question

Kibishi

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itakiamo

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Kibishi

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Cndoh Jr

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