a) if A + B + C= 180 degrees ,prove that sin(B+C-A) + sin (C + A-B)+ Sin (A+ B+C)= 4sin A sinB sinC
a) if A + B + C= 180 degrees ,prove that sin(B+C-A) + sin (C + A-B)+ Sin (A+ B+C)= 4sin A sinB sinC
Mama Mdogo umenikumbusha enzi hizo nipo katika kiwango bora kabisa katka hili somo.
Mama Mdogo umenikumbusha enzi hizo nipo katika kiwango bora kabisa katka hili somo.
Hongera kijana. Sisi tulisoma enzi zile za Hesabu za Ushirika (Primary), Mathematics for Tanzanian schools (O level Secondary) na Advanced Mathematics (A level) na Pure and Applied Mathematics for Scientists (University).
Issue: if A + B + C= 180 degrees ,prove that sin(B+C-A) + sin (C + A-B)+ Sin (A+ B+C)= 4sin A sinB sinC
Solution:
If A+B+C=180 degree, then: A+B=180-C (law of subtraction)
hence sin(A+B) = sinC, cos(A+B)=-cosC (law of trigonometry)
then: sin2A + sin 2B +sin2C = 2 sin(A+B)cos(A-B) + 2sinC cosC
=2sinC cos(A-B)+2sinC cosC
=2sinC (cos(A-b) + cos C)
=2sin C(cos(A-B) - cos(A+B) )
= 2sinC . 2sin A sin B
=4 sinA sin B sin C
Tusoviee sasaaaa
Hongera kijana. Sisi tulisoma enzi zile za Hesabu za Ushirika (Primary), Mathematics for Tanzanian schools (O level Secondary) na Advanced Mathematics (A level) na Pure and Applied Mathematics for Scientists (University).
Haha.. Sasa hivi nishazeeka. Labda nimlete mwanangu Lilian atusaidie.
Mi nna alege na hili somo aisee
This is not a sln to this eqn ruther it is a sln for sin2A + sin2B +sin2C=4sinAsinBsinCNimependa unavokata nyanga yaani kitaalam bila blah blah. Very good!