Kelvin Joseph
Member
- Mar 22, 2011
- 11
- 0
hyo hesab co... Jst wtchot
if x=y then,
2x-2y=0 and x-y=0. Thats over... t cnt go fthr
Let a=b
[multiply both sides by b];
ab=b^2
(minus a^2 both sides);
ab-a^2=b^2-a^2
[factor out the LHS using distributive law and use the difference in square for RHS];
a(b-a)=(b-a)(b + a)
divide by (b-a) both sides;
a=(b + a),
now remember
a=b
then;
a=(a + a)
au a=2a,
divide by a for both LHS and RHS;
a/a=2a/a,
then 1=2
Alternative way
Angalia hii!
Let a=b, upo sawa
then ab=b^2, it's ok
ab-a^2=b^2-a^2, true.
Olso a(b-a)=(b-a)(b+a) it's ok!
But, u can't divide throughout by (b-a) since a=b, then b-a=0. So the equation is meaningless since you are trying to dived by zero. Kwahiyo basi, moja haiwezi kuwa sawa na mbili hata mwisho wa dunia!!