Height of maths logic..

[Mkaa Mweupe]

Kwa Challenge just use any mathematical operation to prove the folloving:

1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

Chemsha bongo!

1 1 1 = 6
(1+1+1)! = 6

2 2 2 = 6
2+2+2 = 6

3 3 3 = 6
(3*3) - 3 = 6

4 4 4 = 6
sqr4 + sqr4 + sqr4 = 6

5 5 5 = 6
5+(5/5) = 6

6 6 6 = 6
6*(6/6) = 6

7 7 7 = 6
7-(7/7) = 6

8 8 8 = 6
cubr8 + cubr8 + cubr8 = 6

9 9 9 = 6
(sqr9 * sqr9) - sqr9 = 6

Hence proved!