Haya maswali yanahusu
electronic configuration. Tuyaweke hatua kwa hatua kama kwenye karatasi ya mtihani.
1. Write the electronic configuration of an atom with 25 electrons.
Atom yenye elektroni 25 ina
atomic number 25, ambayo ni element ya Manganese (Mn).
Mpangilio wa elektroni:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵
Au kwa kifupi:
[Ar] 4s² 3d⁵
2. State the period and group of an element with atomic number 30.
Atomic number 30 ni Zinc.
Electronic configuration:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰
Period
Namba kubwa zaidi ya energy level ni
4 (4s²).
Period = 4
Group
Kwa transition elements:
Group = electrons za (n−1)d + ns
= 10 + 2
= 12
Group = 12
Jibu: Period 4, Group 12.
3. An element X has the electronic configuration:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵
(a) Identify the element.
Jumla ya elektroni:
2 + 2 + 6 + 2 + 6 + 2 + 5 = 25
Atomic number = 25
Element ni
Manganese (Mn).
(b) State its atomic number.
Atomic number =
25
4. Explain why the electronic configuration of Copper (Z = 29) is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d¹⁰
and not 4s² 3d⁹.
Kwa kawaida tungetarajia:
[Ar] 4s² 3d⁹
Lakini atomu ya Copper hupanga elektroni zake kuwa:
[Ar] 4s¹ 3d¹⁰
kwa sababu
3d¹⁰ ni subshell iliyojazwa kikamilifu (fully filled d-subshell) na huwa imara zaidi (more stable) kuliko 3d⁹.
Kwa hiyo elektroni moja kutoka 4s huhamia 3d ili kufanya 3d iwe na elektroni 10 kamili.
Jibu la maelezo:
Copper has the configuration
4s¹ 3d¹⁰ because a completely filled
3d-subshell (3d¹⁰) is more stable than a partially filled
3d⁹ subshell. Therefore, one electron moves from the 4s orbital to the 3d orbital, giving the more stable arrangement
4s¹ 3d¹⁰.
Muhtasari wa Majibu
| Swali | Jibu |
|---|
| 1 | 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵ |
| 2 | Period 4, Group 12 |
| 3(a) | Manganese (Mn) |
| 3(b) | Atomic number 25 |
| 4 | Copper has 4s¹ 3d¹⁰ because a fully filled 3d-subshell is more stable than 4s² 3d⁹.
Chanzo : AI |