Freyzem
JF-Expert Member
- Jun 29, 2013
- 10,120
- 24,667
- Thread starter
-
- #4,621
QUESTION
If Bournemouth beat Chelsea 3-0 and Watford beat Chelsea 4-1, Assuming momentum before collision = momentum after collision and forces applied to a rigid body all act in the same plane, calculate the number of goals Barcelona will score against Chelsea. (Take g=9.8m/s2)
SOLUTION
Given that g= 9.8m/s^2...{ let Chelsea be denoted as C, Bournemouth be denoted as B, and Watford is denoted by W}
3B+ 0C = 3......Eqn 1
4W + (-1) = 3...Eqn 2
The cumulative goal conceded is {3+3 =6}
Let cumulative be denoted as "a"
Therefore, if Barca denoted as Br
Squad strength of barca = a+1
Messi probability to score = a+1+1
Chelsea being a team of dog turds = a+1+1+1
Note a=6
Therefore, a+3 =6+3=9
9 goals.
[emoji474]♂
[emoji23][emoji23][emoji23][emoji23][emoji23]
If Bournemouth beat Chelsea 3-0 and Watford beat Chelsea 4-1, Assuming momentum before collision = momentum after collision and forces applied to a rigid body all act in the same plane, calculate the number of goals Barcelona will score against Chelsea. (Take g=9.8m/s2)
SOLUTION
Given that g= 9.8m/s^2...{ let Chelsea be denoted as C, Bournemouth be denoted as B, and Watford is denoted by W}
3B+ 0C = 3......Eqn 1
4W + (-1) = 3...Eqn 2
The cumulative goal conceded is {3+3 =6}
Let cumulative be denoted as "a"
Therefore, if Barca denoted as Br
Squad strength of barca = a+1
Messi probability to score = a+1+1
Chelsea being a team of dog turds = a+1+1+1
Note a=6
Therefore, a+3 =6+3=9
9 goals.
[emoji474]♂
[emoji23][emoji23][emoji23][emoji23][emoji23]