Mwanza University yafungiwa na TCU, wanafunzi wahamishiwa CUHAS

[hydroxo]

Okay Sawa, usitumie nguvu nyingi sana..
Hebu tunaomba weka screenshot ya TCU yenye kuonesha minimum entry ya kusoma digrii ya udaktari.
Hapo ndo tutajua kama je mwenye Div 2 anaruhusiwa au haruhusiwi

 

[Matawi ya juu]

A toy car with mass 1.5 kg starts from rest and takes 8 seconds to reaches constant velocity of 30m/s before it hit the wall, calculate the force of the impact

F = ma

 

[AXIOM APEX VERBOSE]

A toy car with mass 1.5 kg starts from rest and takes 8 seconds to reaches constant velocity of 30m/s before it hit the wall, calculate the force of the impact

Need one more assumption: impact force depends on how quickly the car stops (impact duration or stopping distance). I'll compute force for two common assumptions—a) stopping time, b) stopping distance—then you can pick which fits.

Given: m = 1.5 kg, initial speed before impact v = 30 m/s.

1) If you assume the car stops in time Δt (s):

• deceleration a = −v / Δt = −30 / Δt (m/s^2)
• impact force magnitude F = m * |a| = m * 30 / Δt = (1.5 * 30) / Δt = 45 / Δt (N)

Examples:

• Δt = 0.01 s → F = 45 / 0.01 = 4500 N
• Δt = 0.001 s → F = 45 / 0.001 = 45,000 N

2) If you assume the car stops over distance d (m) with uniform deceleration:

• a = −v^2 / (2d) = −(30^2) / (2d) = −900 / (2d) = −450 / d (m/s^2)
• F = m * |a| = 1.5 * 450 / d = 675 / d (N)

Examples:

• d = 0.1 m → F = 675 / 0.1 = 6,750 N
• d = 0.02 m → F = 675 / 0.02 = 33,750 N

If you provide a stopping time or distance (or coefficient of restitution for a bounce), I’ll give the numeric impact force.

 

[The Gworl]

Faragha za watu hizo mkuu ila wapo wengi sana mtu ana division 2 wanachukua sijajua wanafanyaje ad anadahiliwa

Huo udaktari wawapi lbd udaktari vyuo vya serikali ni division 1 ya 3 hadi 6 saba labda wakuhurumie tu sasa wewe unaposema div 2 asome MD degree nayo ijua mimi haiwezekani lbd utafutilize vyuo vya uchocholoni huku km hivi vya MZ

Kijana ni saumu Kali au kitu Gani? Kwanini umechagua kuweka ujinga wazi wazi..🥺🥺

 

[Zongh]

Huo udaktari wawapi lbd udaktari vyuo vya serikali ni division 1 ya 3 hadi 6 saba labda wakuhurumie tu sasa wewe unaposema div 2 asome MD degree nayo ijua mimi haiwezekani lbd utafutilize vyuo vya uchocholoni huku km hivi vya MZ

Wewe jamaa nimegundua wewe sio mtu wa afya na hujui chochote kile unapayuka tuu kutokana na uliyosikia mtandaoni

Hebu fanya u deal na mambo yanayokusu usiogelee sekta usiyoijua

 

[MONEY IS NOT EVERYTHING]

Aiseee ! Hz biashara zingine za elimu bora TCU inazistukia.

 

[Makebo]

Need one more assumption: impact force depends on how quickly the car stops (impact duration or stopping distance). I'll compute force for two common assumptions—a) stopping time, b) stopping distance—then you can pick which fits.

Given: m = 1.5 kg, initial speed before impact v = 30 m/s.

1) If you assume the car stops in time Δt (s):

• deceleration a = −v / Δt = −30 / Δt (m/s^2)
• impact force magnitude F = m * |a| = m * 30 / Δt = (1.5 * 30) / Δt = 45 / Δt (N)

Examples:

• Δt = 0.01 s → F = 45 / 0.01 = 4500 N
• Δt = 0.001 s → F = 45 / 0.001 = 45,000 N

2) If you assume the car stops over distance d (m) with uniform deceleration:

• a = −v^2 / (2d) = −(30^2) / (2d) = −900 / (2d) = −450 / d (m/s^2)
• F = m * |a| = 1.5 * 450 / d = 675 / d (N)

Examples:

• d = 0.1 m → F = 675 / 0.1 = 6,750 N
• d = 0.02 m → F = 675 / 0.02 = 33,750 N

If you provide a stopping time or distance (or coefficient of restitution for a bounce), I’ll give the numeric impact force.

Mwambie huyo akili unde akurudishie hela yako

 

[Superbug]

Need one more assumption: impact force depends on how quickly the car stops (impact duration or stopping distance). I'll compute force for two common assumptions—a) stopping time, b) stopping distance—then you can pick which fits.

Given: m = 1.5 kg, initial speed before impact v = 30 m/s.

1) If you assume the car stops in time Δt (s):

• deceleration a = −v / Δt = −30 / Δt (m/s^2)
• impact force magnitude F = m * |a| = m * 30 / Δt = (1.5 * 30) / Δt = 45 / Δt (N)

Examples:

• Δt = 0.01 s → F = 45 / 0.01 = 4500 N
• Δt = 0.001 s → F = 45 / 0.001 = 45,000 N

2) If you assume the car stops over distance d (m) with uniform deceleration:

• a = −v^2 / (2d) = −(30^2) / (2d) = −900 / (2d) = −450 / d (m/s^2)
• F = m * |a| = 1.5 * 450 / d = 675 / d (N)

Examples:

• d = 0.1 m → F = 675 / 0.1 = 6,750 N
• d = 0.02 m → F = 675 / 0.02 = 33,750 N

If you provide a stopping time or distance (or coefficient of restitution for a bounce), I’ll give the numeric impact force.

Mungu alininyima ubongo wa kuelewa haya madude.

 

[Benzodiazepine]

View attachment 3549287

Uzi umeishia hapa, Tuufunge huu mjadala.

Maana mtaani watu wanaongea ongea tu pasipo kuelewa.
Natumaini mleta mada sasa atakuwa ameelewa somo.

 

[verify]

A toy car with mass 1.5 kg starts from rest and takes 8 seconds to reaches constant velocity of 30m/s before it hit the wall, calculate the force of the impact

1: finding acceleration
a= v-u/t
a=30-0/8
a=3.75m/s²...........(i)

2 finding the required force

F=ma
F=1.5kg×3.75m/s²
F=5.625N.....................(ii)

3. If car stop instantly

P=mv
P=1.5×30
P=45kgm/s
Moment before impact is 45kgm/s

But

F= change P/t
t is not given hence force is 5.625N.

Makebo nisahishie mkuu kama nimepata mana zamani sana 😁😁

 

[NgerukeAbra]

Serikali imekifungia chuo cha Mwanza university wanafunzi wadai pesa za takribani million 73 ambapo uongozi ulidai zitahamishiwa Bugando..

Kama mnavojua Watanzania njaa sana hiki chuo kuna wanafunzi wamepachikwa tu not qualified to study medicine hukoo Bugando watapokelewa na nani?

It's better wakapewa pesa zao wafanye mambo mengine.

Hilo eneo linamkosi St. Mary's walipakimbia na hawa tena wamepakimbia.

Chuo kipo Nyamhongolo

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