ngoja nianze wengine watakomenti kama ni sawa.
given H=9m
*find final velocity, V.
V=√2gh =√(2×9.8×9)
V= 13.28m/s.
After bouncing, the above final velocity will act as initial velocity(U)
from newton's third law of motion:
v^2=u^2+2gh , find final velocity v'.
v^2=(13.28 )^2 +2×9.8×9
v'=18.76m/s.
Then; V×H=v'×h ,find h,
h= (13.28×9)÷18.76
h=6.37m (utaenda juu mita 6.37)
Inategemea na coefficient of restitution kati ya mpira na hiyo surface utakapodunda.
Your red statement is only true if the coefficient of restitution between the ball and the surface is 1.0 (almost impossible).
Think of it this way, if the ball hits a swimming pool full of water (coefficient of restitution = 0.0) the ball will never bounce back.