Kiranga
Platinum Member
- Jan 29, 2009
- 78,790
- 128,275
Nimeitest na simultaneous equation hapa.
Swali.
if 2x + 3y = 22 and 7x + 12y =86, what is x ? what is y?
Jibu.
To solve for x and y, we can use the method of substitution.
From the first equation, we can solve for x in terms of y:
2x + 3y = 22
2x = 22 - 3y
x = (22 - 3y)/2
Now we can substitute this expression for x into the second equation:
7x + 12y = 86
7[(22 - 3y)/2] + 12y = 86
Multiplying both sides by 2 to eliminate the fraction:
7(22 - 3y) + 24y = 172
154 - 21y + 24y = 172
3y = 18 y = 6
Now that we have solved for y, we can substitute this value back into the equation we derived for x:
x = (22 - 3y)/2 = (22 - 3(6))/2 = 4
Therefore, the solution is x = 4 and y = 6.
Swali.
if 2x + 3y = 22 and 7x + 12y =86, what is x ? what is y?
Jibu.
To solve for x and y, we can use the method of substitution.
From the first equation, we can solve for x in terms of y:
2x + 3y = 22
2x = 22 - 3y
x = (22 - 3y)/2
Now we can substitute this expression for x into the second equation:
7x + 12y = 86
7[(22 - 3y)/2] + 12y = 86
Multiplying both sides by 2 to eliminate the fraction:
7(22 - 3y) + 24y = 172
154 - 21y + 24y = 172
3y = 18 y = 6
Now that we have solved for y, we can substitute this value back into the equation we derived for x:
x = (22 - 3y)/2 = (22 - 3(6))/2 = 4
Therefore, the solution is x = 4 and y = 6.